Container N and P are identical containers with the same base area and height. Container N is filled to the brim with water while Container P is empty. After 242 cm³ of water from Container N is poured into Container P, the depth of water in Container P is ¹₉ the depth of water in Container N. If the height of Container P is 22 cm, what is the base area of Container P?
The depth of water is proportional to the volume of water.

After water from Container N is poured into Container P:

Volume of water in Container N : Volume of water in Container P
 9 : 1

1 u = 242

Total volume of Container P
= 9 u + 1 u
= 10 u
= 10 x 242
= 2420 cm³

Base area of Container P
= 2420 ÷ 22
= 110 cm²

Answer(s): 110 cm²