Container H and J are identical containers with the same base area and height. Container H is filled to the brim with water while Container J is empty. After 288 cm³ of water from Container H is poured into Container J, the depth of water in Container J is ¹₆ the depth of water in Container H. If the height of Container J is 24 cm, what is the base area of Container J?
The depth of water is proportional to the volume of water.

After water from Container H is poured into Container J:

Volume of water in Container H : Volume of water in Container J
 6 : 1

1 u = 288

Total volume of Container J
= 6 u + 1 u
= 7 u
= 7 x 288
= 2016 cm³

Base area of Container J
= 2016 ÷ 24
= 84 cm²

Answer(s): 84 cm²