Container L and M are identical containers with the same base area and height. Container L is filled to the brim with water while Container M is empty. After 290 cm³ of water from Container L is poured into Container M, the depth of water in Container M is ¹₇ the depth of water in Container L. If the height of Container M is 29 cm, what is the base area of Container M?
The depth of water is proportional to the volume of water.

After water from Container L is poured into Container M:

Volume of water in Container L : Volume of water in Container M
 7 : 1

1 u = 290

Total volume of Container M
= 7 u + 1 u
= 8 u
= 8 x 290
= 2320 cm³

Base area of Container M
= 2320 ÷ 29
= 80 cm²

Answer(s): 80 cm²