Container R and S are identical containers with the same base area and height. Container R is filled to the brim with water while Container S is empty. After 285 cm³ of water from Container R is poured into Container S, the depth of water in Container S is ¹₅ the depth of water in Container R. If the height of Container S is 45 cm, what is the base area of Container S?
The depth of water is proportional to the volume of water.

After water from Container R is poured into Container S:

Volume of water in Container R : Volume of water in Container S
 5 : 1

1 u = 285

Total volume of Container S
= 5 u + 1 u
= 6 u
= 6 x 285
= 1710 cm³

Base area of Container S
= 1710 ÷ 45
= 38 cm²

Answer(s): 38 cm²