Container S and T are identical containers with the same base area and height. Container S is filled to the brim with water while Container T is empty. After 287 cm³ of water from Container S is poured into Container T, the depth of water in Container T is ¹₃ the depth of water in Container S. If the height of Container T is 41 cm, what is the base area of Container T?
The depth of water is proportional to the volume of water.

After water from Container S is poured into Container T:

Volume of water in Container S : Volume of water in Container T
 3 : 1

1 u = 287

Total volume of Container T
= 3 u + 1 u
= 4 u
= 4 x 287
= 1148 cm³

Base area of Container T
= 1148 ÷ 41
= 28 cm²

Answer(s): 28 cm²