A cylindrical dispenser of capacity 6.3 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 18 cm, through a tap flowing at a rate of 200 mℓ /min. After 19 min, the tap was turned off and the container was
23 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 200 x 19
= 3800 mℓ
1 ℓ = 1000 mℓ
3.8 ℓ = 3800 mℓ
Volume of chikoo juice Left in the dispenser
= 6.3 - 3.8
= 2.5 ℓ
Percentage of chikoo juice Left in the dispenser
= 2.5 ÷ 6.3 x 100
= 39.68253968254%
≈ 39.68% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 23 x 18 x 18 x 18 = 3888 cm
3
Amount of chikoo juice in the container at first
= 3888 - 3800
= 88 cm
3 1000 cm³ = 1 ℓ
88 cm
3 = 0.088 ℓ
Answer(s): (a) 39.68%; (b) 0.088 ℓ