A cylindrical dispenser of capacity 5.1 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 298 mℓ /min. After 14 min, the tap was turned off and the container was
35 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 298 x 14
= 4172 mℓ
1 ℓ = 1000 mℓ
4.172 ℓ = 4172 mℓ
Volume of chikoo juice Left in the dispenser
= 5.1 - 4.172
= 0.928 ℓ
Percentage of chikoo juice Left in the dispenser
= 0.928 ÷ 5.1 x 100
= 18.196078431373%
≈ 18.20% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 35 x 20 x 20 x 20 = 4800 cm
3
Amount of chikoo juice in the container at first
= 4800 - 4172
= 628 cm
3 1000 cm³ = 1 ℓ
628 cm
3 = 0.628 ℓ
Answer(s): (a) 18.20%; (b) 0.628 ℓ