A cylindrical dispenser of capacity 6.6 ℓ was filled with grapefruit juice to its brim. The grapefruit juice in the dispenser was then dispensed into a cubical container of sides 15 cm, through a tap flowing at a rate of 111 mℓ /min. After 18 min, the tap was turned off and the container was
23 full.
- What percentage of the grapefruit juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of grapefruit juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of grapefruit juice that was dispensed
= 111 x 18
= 1998 mℓ
1 ℓ = 1000 mℓ
1.998 ℓ = 1998 mℓ
Volume of grapefruit juice Left in the dispenser
= 6.6 - 1.998
= 4.602 ℓ
Percentage of grapefruit juice Left in the dispenser
= 4.602 ÷ 6.6 x 100
= 69.727272727273%
≈ 69.73% (to 2 decimal places)
(b)
Amount of grapefruit juice in the container in the end
= 23 x 15 x 15 x 15 = 2250 cm
3
Amount of grapefruit juice in the container at first
= 2250 - 1998
= 252 cm
3 1000 cm³ = 1 ℓ
252 cm
3 = 0.252 ℓ
Answer(s): (a) 69.73%; (b) 0.252 ℓ