A cylindrical dispenser of capacity 6.6 ℓ was filled with pear juice to its brim. The pear juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 191 mℓ /min. After 14 min, the tap was turned off and the container was
25 full.
- What percentage of the pear juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of pear juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of pear juice that was dispensed
= 191 x 14
= 2674 mℓ
1 ℓ = 1000 mℓ
2.674 ℓ = 2674 mℓ
Volume of pear juice Left in the dispenser
= 6.6 - 2.674
= 3.926 ℓ
Percentage of pear juice Left in the dispenser
= 3.926 ÷ 6.6 x 100
= 59.484848484848%
≈ 59.48% (to 2 decimal places)
(b)
Amount of pear juice in the container in the end
= 25 x 20 x 20 x 20 = 3200 cm
3
Amount of pear juice in the container at first
= 3200 - 2674
= 526 cm
3 1000 cm³ = 1 ℓ
526 cm
3 = 0.526 ℓ
Answer(s): (a) 59.48%; (b) 0.526 ℓ