A cylindrical dispenser of capacity 6.3 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 18 cm, through a tap flowing at a rate of 281 mℓ /min. After 11 min, the tap was turned off and the container was
23 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 281 x 11
= 3091 mℓ
1 ℓ = 1000 mℓ
3.091 ℓ = 3091 mℓ
Volume of chikoo juice Left in the dispenser
= 6.3 - 3.091
= 3.209 ℓ
Percentage of chikoo juice Left in the dispenser
= 3.209 ÷ 6.3 x 100
= 50.936507936508%
≈ 50.94% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 23 x 18 x 18 x 18 = 3888 cm
3
Amount of chikoo juice in the container at first
= 3888 - 3091
= 797 cm
3 1000 cm³ = 1 ℓ
797 cm
3 = 0.797 ℓ
Answer(s): (a) 50.94%; (b) 0.797 ℓ