A cylindrical dispenser of capacity 6.1 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 294 mℓ /min. After 12 min, the tap was turned off and the container was
35 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 294 x 12
= 3528 mℓ
1 ℓ = 1000 mℓ
3.528 ℓ = 3528 mℓ
Volume of chikoo juice Left in the dispenser
= 6.1 - 3.528
= 2.572 ℓ
Percentage of chikoo juice Left in the dispenser
= 2.572 ÷ 6.1 x 100
= 42.16393442623%
≈ 42.16% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 35 x 20 x 20 x 20 = 4800 cm
3
Amount of chikoo juice in the container at first
= 4800 - 3528
= 1272 cm
3 1000 cm³ = 1 ℓ
1272 cm
3 = 1.272 ℓ
Answer(s): (a) 42.16%; (b) 1.272 ℓ