A cylindrical dispenser of capacity 5.8 ℓ was filled with guava juice to its brim. The guava juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 105 mℓ /min. After 17 min, the tap was turned off and the container was
14 full.
- What percentage of the guava juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of guava juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of guava juice that was dispensed
= 105 x 17
= 1785 mℓ
1 ℓ = 1000 mℓ
1.785 ℓ = 1785 mℓ
Volume of guava juice Left in the dispenser
= 5.8 - 1.785
= 4.015 ℓ
Percentage of guava juice Left in the dispenser
= 4.015 ÷ 5.8 x 100
= 69.224137931034%
≈ 69.22% (to 2 decimal places)
(b)
Amount of guava juice in the container in the end
= 14 x 20 x 20 x 20 = 2000 cm
3
Amount of guava juice in the container at first
= 2000 - 1785
= 215 cm
3 1000 cm³ = 1 ℓ
215 cm
3 = 0.215 ℓ
Answer(s): (a) 69.22%; (b) 0.215 ℓ