A cylindrical dispenser of capacity 6.5 ℓ was filled with pear juice to its brim. The pear juice in the dispenser was then dispensed into a cubical container of sides 18 cm, through a tap flowing at a rate of 324 mℓ /min. After 11 min, the tap was turned off and the container was
23 full.
- What percentage of the pear juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of pear juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of pear juice that was dispensed
= 324 x 11
= 3564 mℓ
1 ℓ = 1000 mℓ
3.564 ℓ = 3564 mℓ
Volume of pear juice Left in the dispenser
= 6.5 - 3.564
= 2.936 ℓ
Percentage of pear juice Left in the dispenser
= 2.936 ÷ 6.5 x 100
= 45.169230769231%
≈ 45.17% (to 2 decimal places)
(b)
Amount of pear juice in the container in the end
= 23 x 18 x 18 x 18 = 3888 cm
3
Amount of pear juice in the container at first
= 3888 - 3564
= 324 cm
3 1000 cm³ = 1 ℓ
324 cm
3 = 0.324 ℓ
Answer(s): (a) 45.17%; (b) 0.324 ℓ