A cylindrical dispenser of capacity 5.3 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 145 mℓ /min. After 11 min, the tap was turned off and the container was
45 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 145 x 11
= 1595 mℓ
1 ℓ = 1000 mℓ
1.595 ℓ = 1595 mℓ
Volume of chikoo juice Left in the dispenser
= 5.3 - 1.595
= 3.705 ℓ
Percentage of chikoo juice Left in the dispenser
= 3.705 ÷ 5.3 x 100
= 69.905660377358%
≈ 69.91% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 45 x 20 x 20 x 20 = 6400 cm
3
Amount of chikoo juice in the container at first
= 6400 - 1595
= 4805 cm
3 1000 cm³ = 1 ℓ
4805 cm
3 = 4.805 ℓ
Answer(s): (a) 69.91%; (b) 4.805 ℓ