A cylindrical dispenser of capacity 6.1 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 15 cm, through a tap flowing at a rate of 165 mℓ /min. After 13 min, the tap was turned off and the container was ²₃ full.

1. What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
2. How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm³)

(a)
Volume of chikoo juice that was dispensed
= 165 x 13
= 2145 mℓ

1 ℓ = 1000 mℓ
2.145 ℓ = 2145 mℓ

Volume of chikoo juice Left in the dispenser
= 6.1 - 2.145
= 3.955 ℓ

Percentage of chikoo juice Left in the dispenser
= 3.955 ÷ 6.1 x 100
= 64.83606557377%
≈ 64.84% (to 2 decimal places)

(b)
Amount of chikoo juice in the container in the end
= ²₃ x 15 x 15 x 15
= 2250 cm³

Amount of chikoo juice in the container at first
= 2250 - 2145
= 105 cm³

1000 cm³ = 1  ℓ
105 cm³ = 0.105 ℓ

Answer(s): (a) 64.84%; (b) 0.105 ℓ