A cylindrical dispenser of capacity 6.4 ℓ was filled with pear juice to its brim. The pear juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 144 mℓ /min. After 21 min, the tap was turned off and the container was
45 full.
- What percentage of the pear juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of pear juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of pear juice that was dispensed
= 144 x 21
= 3024 mℓ
1 ℓ = 1000 mℓ
3.024 ℓ = 3024 mℓ
Volume of pear juice Left in the dispenser
= 6.4 - 3.024
= 3.376 ℓ
Percentage of pear juice Left in the dispenser
= 3.376 ÷ 6.4 x 100
= 52.75%
≈ 52.75% (to 2 decimal places)
(b)
Amount of pear juice in the container in the end
= 45 x 20 x 20 x 20 = 6400 cm
3
Amount of pear juice in the container at first
= 6400 - 3024
= 3376 cm
3 1000 cm³ = 1 ℓ
3376 cm
3 = 3.376 ℓ
Answer(s): (a) 52.75%; (b) 3.376 ℓ