A cylindrical dispenser of capacity 6.2 ℓ was filled with grapefruit juice to its brim. The grapefruit juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 347 mℓ /min. After 11 min, the tap was turned off and the container was
35 full.
- What percentage of the grapefruit juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of grapefruit juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of grapefruit juice that was dispensed
= 347 x 11
= 3817 mℓ
1 ℓ = 1000 mℓ
3.817 ℓ = 3817 mℓ
Volume of grapefruit juice Left in the dispenser
= 6.2 - 3.817
= 2.383 ℓ
Percentage of grapefruit juice Left in the dispenser
= 2.383 ÷ 6.2 x 100
= 38.435483870968%
≈ 38.44% (to 2 decimal places)
(b)
Amount of grapefruit juice in the container in the end
= 35 x 20 x 20 x 20 = 4800 cm
3
Amount of grapefruit juice in the container at first
= 4800 - 3817
= 983 cm
3 1000 cm³ = 1 ℓ
983 cm
3 = 0.983 ℓ
Answer(s): (a) 38.44%; (b) 0.983 ℓ