A cylindrical dispenser of capacity 6.3 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 16 cm, through a tap flowing at a rate of 175 mℓ /min. After 15 min, the tap was turned off and the container was
34 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 175 x 15
= 2625 mℓ
1 ℓ = 1000 mℓ
2.625 ℓ = 2625 mℓ
Volume of chikoo juice Left in the dispenser
= 6.3 - 2.625
= 3.675 ℓ
Percentage of chikoo juice Left in the dispenser
= 3.675 ÷ 6.3 x 100
= 58.333333333333%
≈ 58.33% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 34 x 16 x 16 x 16 = 3072 cm
3
Amount of chikoo juice in the container at first
= 3072 - 2625
= 447 cm
3 1000 cm³ = 1 ℓ
447 cm
3 = 0.447 ℓ
Answer(s): (a) 58.33%; (b) 0.447 ℓ