A cylindrical dispenser of capacity 5.5 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 184 mℓ /min. After 24 min, the tap was turned off and the container was
34 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 184 x 24
= 4416 mℓ
1 ℓ = 1000 mℓ
4.416 ℓ = 4416 mℓ
Volume of chikoo juice Left in the dispenser
= 5.5 - 4.416
= 1.084 ℓ
Percentage of chikoo juice Left in the dispenser
= 1.084 ÷ 5.5 x 100
= 19.709090909091%
≈ 19.71% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 34 x 20 x 20 x 20 = 6000 cm
3
Amount of chikoo juice in the container at first
= 6000 - 4416
= 1584 cm
3 1000 cm³ = 1 ℓ
1584 cm
3 = 1.584 ℓ
Answer(s): (a) 19.71%; (b) 1.584 ℓ