A cylindrical dispenser of capacity 5.2 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 18 cm, through a tap flowing at a rate of 217 mℓ /min. After 12 min, the tap was turned off and the container was
34 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 217 x 12
= 2604 mℓ
1 ℓ = 1000 mℓ
2.604 ℓ = 2604 mℓ
Volume of chikoo juice Left in the dispenser
= 5.2 - 2.604
= 2.596 ℓ
Percentage of chikoo juice Left in the dispenser
= 2.596 ÷ 5.2 x 100
= 49.923076923077%
≈ 49.92% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 34 x 18 x 18 x 18 = 4374 cm
3
Amount of chikoo juice in the container at first
= 4374 - 2604
= 1770 cm
3 1000 cm³ = 1 ℓ
1770 cm
3 = 1.77 ℓ
Answer(s): (a) 49.92%; (b) 1.77 ℓ