A cylindrical dispenser of capacity 6.2 ℓ was filled with pear juice to its brim. The pear juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 117 mℓ /min. After 10 min, the tap was turned off and the container was
35 full.
- What percentage of the pear juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of pear juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of pear juice that was dispensed
= 117 x 10
= 1170 mℓ
1 ℓ = 1000 mℓ
1.17 ℓ = 1170 mℓ
Volume of pear juice Left in the dispenser
= 6.2 - 1.17
= 5.03 ℓ
Percentage of pear juice Left in the dispenser
= 5.03 ÷ 6.2 x 100
= 81.129032258065%
≈ 81.13% (to 2 decimal places)
(b)
Amount of pear juice in the container in the end
= 35 x 20 x 20 x 20 = 4800 cm
3
Amount of pear juice in the container at first
= 4800 - 1170
= 3630 cm
3 1000 cm³ = 1 ℓ
3630 cm
3 = 3.63 ℓ
Answer(s): (a) 81.13%; (b) 3.63 ℓ