A cylindrical dispenser of capacity 6.3 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 18 cm, through a tap flowing at a rate of 167 mℓ /min. After 21 min, the tap was turned off and the container was
23 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 167 x 21
= 3507 mℓ
1 ℓ = 1000 mℓ
3.507 ℓ = 3507 mℓ
Volume of chikoo juice Left in the dispenser
= 6.3 - 3.507
= 2.793 ℓ
Percentage of chikoo juice Left in the dispenser
= 2.793 ÷ 6.3 x 100
= 44.333333333333%
≈ 44.33% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 23 x 18 x 18 x 18 = 3888 cm
3
Amount of chikoo juice in the container at first
= 3888 - 3507
= 381 cm
3 1000 cm³ = 1 ℓ
381 cm
3 = 0.381 ℓ
Answer(s): (a) 44.33%; (b) 0.381 ℓ