A cylindrical dispenser of capacity 5.8 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 120 mℓ /min. After 14 min, the tap was turned off and the container was
25 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 120 x 14
= 1680 mℓ
1 ℓ = 1000 mℓ
1.68 ℓ = 1680 mℓ
Volume of chikoo juice Left in the dispenser
= 5.8 - 1.68
= 4.12 ℓ
Percentage of chikoo juice Left in the dispenser
= 4.12 ÷ 5.8 x 100
= 71.034482758621%
≈ 71.03% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 25 x 20 x 20 x 20 = 3200 cm
3
Amount of chikoo juice in the container at first
= 3200 - 1680
= 1520 cm
3 1000 cm³ = 1 ℓ
1520 cm
3 = 1.52 ℓ
Answer(s): (a) 71.03%; (b) 1.52 ℓ