A cylindrical dispenser of capacity 6.5 ℓ was filled with chikoo juice to its brim. The chikoo juice in the dispenser was then dispensed into a cubical container of sides 15 cm, through a tap flowing at a rate of 129 mℓ /min. After 11 min, the tap was turned off and the container was
23 full.
- What percentage of the chikoo juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of chikoo juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of chikoo juice that was dispensed
= 129 x 11
= 1419 mℓ
1 ℓ = 1000 mℓ
1.419 ℓ = 1419 mℓ
Volume of chikoo juice Left in the dispenser
= 6.5 - 1.419
= 5.081 ℓ
Percentage of chikoo juice Left in the dispenser
= 5.081 ÷ 6.5 x 100
= 78.169230769231%
≈ 78.17% (to 2 decimal places)
(b)
Amount of chikoo juice in the container in the end
= 23 x 15 x 15 x 15 = 2250 cm
3
Amount of chikoo juice in the container at first
= 2250 - 1419
= 831 cm
3 1000 cm³ = 1 ℓ
831 cm
3 = 0.831 ℓ
Answer(s): (a) 78.17%; (b) 0.831 ℓ