A cylindrical dispenser of capacity 5.6 ℓ was filled with pear juice to its brim. The pear juice in the dispenser was then dispensed into a cubical container of sides 20 cm, through a tap flowing at a rate of 196 mℓ /min. After 24 min, the tap was turned off and the container was
45 full.
- What percentage of the pear juice in the cylindrical dispenser was left? Round off your answer to the nearest 2 decimal places.
- How many litres of pear juice were there in the container at first? (1 ℓ = 1000 cm3)
(a)
Volume of pear juice that was dispensed
= 196 x 24
= 4704 mℓ
1 ℓ = 1000 mℓ
4.704 ℓ = 4704 mℓ
Volume of pear juice Left in the dispenser
= 5.6 - 4.704
= 0.896 ℓ
Percentage of pear juice Left in the dispenser
= 0.896 ÷ 5.6 x 100
= 16%
≈ 16.00% (to 2 decimal places)
(b)
Amount of pear juice in the container in the end
= 45 x 20 x 20 x 20 = 6400 cm
3
Amount of pear juice in the container at first
= 6400 - 4704
= 1696 cm
3 1000 cm³ = 1 ℓ
1696 cm
3 = 1.696 ℓ
Answer(s): (a) 16.00%; (b) 1.696 ℓ