The figure, not drawn to scale, is made up of 2 triangles, NUV and SUV. NP is
12 of ST. QR is
45 of NP and the difference between ST and QR is 60 cm. Given that VU = 13 cm, find the area of the entire figure.
NP |
ST |
QR |
1x5 |
2x5 |
|
5x1 |
|
4x1 |
5 u |
10 u |
4 u |
6 u = 60 cm
1 u = 60 ÷ 6 = 10 cm
Length of NP
= 5 u
= 5 x 10
= 50 cm
Length of ST
= 10 u
= 10 x 10
= 100 cm
Length of QR
= 4 u
= 4 x 10
= 40 cm
Area of Triangle NUV
=
12 x 13 x 50
= 325 cm
2 Area of Triangle SVU
=
12 x 13 x 100
= 650 cm
2 Area of Triangle QVU
=
12 x 13 x 40
= 260 cm
2 Area of the figure
= 325 + 650 - 260
= 715 cm
2 Answer(s): 715 cm
2