The figure, not drawn to scale, is made up of 2 triangles, AGH and EGH. AB is
12 of EF. CD is
67 of AB and the difference between EF and CD is 48 cm. Given that HG = 18 cm, find the area of the entire figure.
AB |
EF |
CD |
1x7 |
2x7 |
|
7x1 |
|
6x1 |
7 u |
14 u |
6 u |
8 u = 48 cm
1 u = 48 ÷ 8 = 6 cm
Length of AB
= 7 u
= 7 x 6
= 42 cm
Length of EF
= 14 u
= 14 x 6
= 84 cm
Length of CD
= 6 u
= 6 x 6
= 36 cm
Area of Triangle AGH
=
12 x 18 x 42
= 378 cm
2 Area of Triangle EHG
=
12 x 18 x 84
= 756 cm
2 Area of Triangle CHG
=
12 x 18 x 36
= 324 cm
2 Area of the figure
= 378 + 756 - 324
= 810 cm
2 Answer(s): 810 cm
2