The figure, not drawn to scale, is made up of 2 triangles, FMN and KMN. FG is
12 of KL. HJ is
56 of FG and the difference between KL and HJ is 42 cm. Given that NM = 18 cm, find the area of the entire figure.
FG |
KL |
HJ |
1x6 |
2x6 |
|
6x1 |
|
5x1 |
6 u |
12 u |
5 u |
7 u = 42 cm
1 u = 42 ÷ 7 = 6 cm
Length of FG
= 6 u
= 6 x 6
= 36 cm
Length of KL
= 12 u
= 12 x 6
= 72 cm
Length of HJ
= 5 u
= 5 x 6
= 30 cm
Area of Triangle FMN
=
12 x 18 x 36
= 324 cm
2 Area of Triangle KNM
=
12 x 18 x 72
= 648 cm
2 Area of Triangle HNM
=
12 x 18 x 30
= 270 cm
2 Area of the figure
= 324 + 648 - 270
= 702 cm
2 Answer(s): 702 cm
2