The figure, not drawn to scale, is made up of 2 triangles, JQR and NQR. JK is
12 of NP. LM is
56 of JK and the difference between NP and LM is 28 cm. Given that RQ = 17 cm, find the area of the entire figure.
JK |
NP |
LM |
1x6 |
2x6 |
|
6x1 |
|
5x1 |
6 u |
12 u |
5 u |
7 u = 28 cm
1 u = 28 ÷ 7 = 4 cm
Length of JK
= 6 u
= 6 x 4
= 24 cm
Length of NP
= 12 u
= 12 x 4
= 48 cm
Length of LM
= 5 u
= 5 x 4
= 20 cm
Area of Triangle JQR
=
12 x 17 x 24
= 204 cm
2 Area of Triangle NRQ
=
12 x 17 x 48
= 408 cm
2 Area of Triangle LRQ
=
12 x 17 x 20
= 170 cm
2 Area of the figure
= 204 + 408 - 170
= 442 cm
2 Answer(s): 442 cm
2