The figure, not drawn to scale, is made up of 2 triangles, JQR and NQR. JK is
12 of NP. LM is
67 of JK and the difference between NP and LM is 64 cm. Given that RQ = 18 cm, find the area of the entire figure.
JK |
NP |
LM |
1x7 |
2x7 |
|
7x1 |
|
6x1 |
7 u |
14 u |
6 u |
8 u = 64 cm
1 u = 64 ÷ 8 = 8 cm
Length of JK
= 7 u
= 7 x 8
= 56 cm
Length of NP
= 14 u
= 14 x 8
= 112 cm
Length of LM
= 6 u
= 6 x 8
= 48 cm
Area of Triangle JQR
=
12 x 18 x 56
= 504 cm
2 Area of Triangle NRQ
=
12 x 18 x 112
= 1008 cm
2 Area of Triangle LRQ
=
12 x 18 x 48
= 432 cm
2 Area of the figure
= 504 + 1008 - 432
= 1080 cm
2 Answer(s): 1080 cm
2