The figure, not drawn to scale, is made up of 2 triangles, BHJ and FHJ. BC is
12 of FG. DE is
67 of BC and the difference between FG and DE is 56 cm. Given that JH = 17 cm, find the area of the entire figure.
BC |
FG |
DE |
1x7 |
2x7 |
|
7x1 |
|
6x1 |
7 u |
14 u |
6 u |
8 u = 56 cm
1 u = 56 ÷ 8 = 7 cm
Length of BC
= 7 u
= 7 x 7
= 49 cm
Length of FG
= 14 u
= 14 x 7
= 98 cm
Length of DE
= 6 u
= 6 x 7
= 42 cm
Area of Triangle BHJ
=
12 x 17 x 49
= 416.5 cm
2 Area of Triangle FJH
=
12 x 17 x 98
= 833 cm
2 Area of Triangle DJH
=
12 x 17 x 42
= 357 cm
2 Area of the figure
= 416.5 + 833 - 357
= 892.5 cm
2 Answer(s): 892.5 cm
2