The figure, not drawn to scale, is made up of 2 triangles, AGH and EGH. AB is
12 of EF. CD is
56 of AB and the difference between EF and CD is 28 cm. Given that HG = 16 cm, find the area of the entire figure.
AB |
EF |
CD |
1x6 |
2x6 |
|
6x1 |
|
5x1 |
6 u |
12 u |
5 u |
7 u = 28 cm
1 u = 28 ÷ 7 = 4 cm
Length of AB
= 6 u
= 6 x 4
= 24 cm
Length of EF
= 12 u
= 12 x 4
= 48 cm
Length of CD
= 5 u
= 5 x 4
= 20 cm
Area of Triangle AGH
=
12 x 16 x 24
= 192 cm
2 Area of Triangle EHG
=
12 x 16 x 48
= 384 cm
2 Area of Triangle CHG
=
12 x 16 x 20
= 160 cm
2 Area of the figure
= 192 + 384 - 160
= 416 cm
2 Answer(s): 416 cm
2