The figure, not drawn to scale, is made up of 2 triangles, HPQ and MPQ. HJ is
12 of MN. KL is
45 of HJ and the difference between MN and KL is 48 cm. Given that QP = 14 cm, find the area of the entire figure.
HJ |
MN |
KL |
1x5 |
2x5 |
|
5x1 |
|
4x1 |
5 u |
10 u |
4 u |
6 u = 48 cm
1 u = 48 ÷ 6 = 8 cm
Length of HJ
= 5 u
= 5 x 8
= 40 cm
Length of MN
= 10 u
= 10 x 8
= 80 cm
Length of KL
= 4 u
= 4 x 8
= 32 cm
Area of Triangle HPQ
=
12 x 14 x 40
= 280 cm
2 Area of Triangle MQP
=
12 x 14 x 80
= 560 cm
2 Area of Triangle KQP
=
12 x 14 x 32
= 224 cm
2 Area of the figure
= 280 + 560 - 224
= 616 cm
2 Answer(s): 616 cm
2