The figure, not drawn to scale, is made up of 2 triangles, BHJ and FHJ. BC is
12 of FG. DE is
67 of BC and the difference between FG and DE is 16 cm. Given that JH = 17 cm, find the area of the entire figure.
BC |
FG |
DE |
1x7 |
2x7 |
|
7x1 |
|
6x1 |
7 u |
14 u |
6 u |
8 u = 16 cm
1 u = 16 ÷ 8 = 2 cm
Length of BC
= 7 u
= 7 x 2
= 14 cm
Length of FG
= 14 u
= 14 x 2
= 28 cm
Length of DE
= 6 u
= 6 x 2
= 12 cm
Area of Triangle BHJ
=
12 x 17 x 14
= 119 cm
2 Area of Triangle FJH
=
12 x 17 x 28
= 238 cm
2 Area of Triangle DJH
=
12 x 17 x 12
= 102 cm
2 Area of the figure
= 119 + 238 - 102
= 255 cm
2 Answer(s): 255 cm
2