The figure, not drawn to scale, is made up of 2 triangles, JQR and NQR. JK is
12 of NP. LM is
67 of JK and the difference between NP and LM is 56 cm. Given that RQ = 17 cm, find the area of the entire figure.
JK |
NP |
LM |
1x7 |
2x7 |
|
7x1 |
|
6x1 |
7 u |
14 u |
6 u |
8 u = 56 cm
1 u = 56 ÷ 8 = 7 cm
Length of JK
= 7 u
= 7 x 7
= 49 cm
Length of NP
= 14 u
= 14 x 7
= 98 cm
Length of LM
= 6 u
= 6 x 7
= 42 cm
Area of Triangle JQR
=
12 x 17 x 49
= 416.5 cm
2 Area of Triangle NRQ
=
12 x 17 x 98
= 833 cm
2 Area of Triangle LRQ
=
12 x 17 x 42
= 357 cm
2 Area of the figure
= 416.5 + 833 - 357
= 892.5 cm
2 Answer(s): 892.5 cm
2