The figure, not drawn to scale, is made up of 2 triangles, NUV and SUV. NP is
12 of ST. QR is
45 of NP and the difference between ST and QR is 42 cm. Given that VU = 14 cm, find the area of the entire figure.
NP |
ST |
QR |
1x5 |
2x5 |
|
5x1 |
|
4x1 |
5 u |
10 u |
4 u |
6 u = 42 cm
1 u = 42 ÷ 6 = 7 cm
Length of NP
= 5 u
= 5 x 7
= 35 cm
Length of ST
= 10 u
= 10 x 7
= 70 cm
Length of QR
= 4 u
= 4 x 7
= 28 cm
Area of Triangle NUV
=
12 x 14 x 35
= 245 cm
2 Area of Triangle SVU
=
12 x 14 x 70
= 490 cm
2 Area of Triangle QVU
=
12 x 14 x 28
= 196 cm
2 Area of the figure
= 245 + 490 - 196
= 539 cm
2 Answer(s): 539 cm
2