The figure, not drawn to scale, is made up of two identical squares, V and X and a rectangle W. The ratio of the area V to the area of W to the area of X is 1 : 2 : 1. The ratio of the unshaded part of V to the unshaded part of X is 3 : 5 respectively. Given that half of the area of V is shaded and the total area of all the shaded parts is 64 cm
2, what is the area of the whole figure?
V |
W |
X |
1x6 = 6 u |
2x6 = 12 u |
1x6 = 6 u |
Unshaded |
Shaded |
Unshaded |
Shaded |
Unshaded |
Shaded |
|
3 |
|
|
5 |
|
1x3 |
1x3 |
|
|
|
|
3 u |
3 u |
8 u |
4 u |
5 u |
1 u |
Since half of the area of V is shaded, the other half of the area of V is unshaded.
Unshaded part of V : Shaded part of V
1 : 1
The unshaded part of V is the repeated identity.
LCM of 1 and 3 = 3
Area of V is the combined repeated identity.
LCM of 1 and 6 = 6
V : W : X
1 : 2 : 1
6 : 12 : 6
Shaded part of V : Shaded part of X
3 : 5
Total shaded area
= 3 u + 1 u
= 4 u
4 u = 64
1 u = 64 ÷ 4 = 16
Area of the whole figure
= 3 u + 12 u + 5 u
= 20 u
= 20 x 16
= 320 cm
2 Answer(s): 320 m
2