The figure, not drawn to scale, is made up of two identical squares, C and E and a rectangle D. The ratio of the area C to the area of D to the area of E is 1 : 2 : 1. The ratio of the unshaded part of C to the unshaded part of E is 2 : 3 respectively. Given that half of the area of C is shaded and the total area of all the shaded parts is 9 cm², what is the area of the whole figure?

C		D		E
1x4 = 4 u		2x4 = 8 u		1x4 = 4 u
Unshaded	Shaded	Unshaded	Shaded	Unshaded	Shaded
	2			3
1x2	1x2
2 u	2 u	5 u	3 u	3 u	1 u

Since half of the area of C is shaded, the other half of the area of C is unshaded.
Unshaded part of C : Shaded part of C
1 : 1

The unshaded part of C is the repeated identity.
LCM of 1 and 2 = 2

Area of C is the combined repeated identity.
LCM of 1 and 4 = 4

C : D : E
1 : 2 : 1
4 : 8 : 4

Shaded part of C : Shaded part of E
2 : 3

Total shaded area
= 2 u + 1 u
= 3 u

3 u = 9

1 u = 9 ÷ 3 = 3

Area of the whole figure
= 2 u + 8 u + 3 u
= 13 u
= 13 x 3 
= 39 cm²

Answer(s): 39 m²