HJKL is a rectangle which has a breadth of 10 m. It is divided into 4 triangles. Triangle M is
113 of the area of the rectangle and
13 the area of Triangle P. Triangle N has an area of 35 m
2.
- Find the area of the rectangle.
- Find the perimeter of the rectangle.
M |
N |
P |
Rectangle |
1 |
|
|
13 |
1 |
|
3 |
|
1 u |
2.5 u |
3 u |
13 u |
(a)
Area of Triangle N
= Half of Rectangle HJKL - Triangle P - Triangle M
= (13 u ÷ 2) - 1 u - 3 u
= 2.5 u
2.5 u = 35
1 u = 35 ÷ 2.5 = 14
Area of the rectangle
= 13 u
= 13 x 14
= 182 m
2 (b)
Length of the rectangle
= 182 ÷ 10
= 18.2 m
Perimeter of the rectangle
= 18.2 x 2 + 10 x 2
= 56.4 m
Answer(s): (a) 182 m
2; (b) 56.4 m