HJKL is a rectangle which has a breadth of 5 m. It is divided into 4 triangles. Triangle M is
111 of the area of the rectangle and
13 the area of Triangle P. Triangle N has an area of 6 m
2.
- Find the area of the rectangle.
- Find the perimeter of the rectangle.
M |
N |
P |
Rectangle |
1 |
|
|
11 |
1 |
|
3 |
|
1 u |
1.5 u |
3 u |
11 u |
(a)
Area of Triangle N
= Half of Rectangle HJKL - Triangle P - Triangle M
= (11 u ÷ 2) - 1 u - 3 u
= 1.5 u
1.5 u = 6
1 u = 6 ÷ 1.5 = 4
Area of the rectangle
= 11 u
= 11 x 4
= 44 m
2 (b)
Length of the rectangle
= 44 ÷ 5
= 8.8 m
Perimeter of the rectangle
= 8.8 x 2 + 5 x 2
= 27.6 m
Answer(s): (a) 44 m
2; (b) 27.6 m