FGHJ is a rectangle which has a breadth of 6 m. It is divided into 4 triangles. Triangle K is
111 of the area of the rectangle and
13 the area of Triangle M. Triangle L has an area of 13.5 m
2.
- Find the area of the rectangle.
- Find the perimeter of the rectangle.
K |
L |
M |
Rectangle |
1 |
|
|
11 |
1 |
|
3 |
|
1 u |
1.5 u |
3 u |
11 u |
(a)
Area of Triangle L
= Half of Rectangle FGHJ - Triangle M - Triangle K
= (11 u ÷ 2) - 1 u - 3 u
= 1.5 u
1.5 u = 13.5
1 u = 13.5 ÷ 1.5 = 9
Area of the rectangle
= 11 u
= 11 x 9
= 99 m
2 (b)
Length of the rectangle
= 99 ÷ 6
= 16.5 m
Perimeter of the rectangle
= 16.5 x 2 + 6 x 2
= 45 m
Answer(s): (a) 99 m
2; (b) 45 m