At the farm, the sheep population increased by 25% in the second month and then by a further 20% in the next 10 months. If there were 600 sheep in the end, how many sheep were there at the farm at first?
| |
Sheep |
| Before |
100% |
| Change 1 |
+ 25% |
| After 1 |
125% |
| Change 2 |
+ 25% |
| After 2 |
150% |
Population of sheep at first = 100%
New population of sheep after first increase
= 100% + 25%
= 125%
Percentage of second increase
= 20% x 125%
=
20100 x 125%
= 25%
New population of sheep after second increase
= 125% + 25%
= 150%
150% of sheep population = 600
1% of the sheep population
= 600 ÷ 150
= 4
100% of sheep population
= 100 x 4
= 400
Number of sheep at first = 400
Answer(s): 400
