At the farm, the sheep population increased by 30% in the second month and then by a further 10% in the next 11 months. If there were 858 sheep in the end, how many sheep were there at the farm at first?
| |
Sheep |
| Before |
100% |
| Change 1 |
+ 30% |
| After 1 |
130% |
| Change 2 |
+ 13% |
| After 2 |
143% |
Population of sheep at first = 100%
New population of sheep after first increase
= 100% + 30%
= 130%
Percentage of second increase
= 10% x 130%
=
10100 x 130%
= 13%
New population of sheep after second increase
= 130% + 13%
= 143%
143% of sheep population = 858
1% of the sheep population
= 858 ÷ 143
= 6
100% of sheep population
= 100 x 6
= 600
Number of sheep at first = 600
Answer(s): 600
