At the farm, the sheep population increased by 30% in the second month and then by a further 20% in the next 10 months. If there were 468 sheep in the end, how many sheep were there at the farm at first?
|
Sheep |
Before |
100% |
Change 1 |
+ 30% |
After 1 |
130% |
Change 2 |
+ 26% |
After 2 |
156% |
Population of sheep at first = 100%
New population of sheep after first increase
= 100% + 30%
= 130%
Percentage of second increase
= 20% x 130%
=
20100 x 130%
= 26%
New population of sheep after second increase
= 130% + 26%
= 156%
156% of sheep population = 468
1% of the sheep population
= 468 ÷ 156
= 3
100% of sheep population
= 100 x 3
= 300
Number of sheep at first = 300
Answer(s): 300