At the farm, the chicken population increased by 20% in the second month and then by a further 5% in the next 3 months. If there were 630 chickens in the end, how many chickens were there at the farm at first?
| |
Chickens |
| Before |
100% |
| Change 1 |
+ 20% |
| After 1 |
120% |
| Change 2 |
+ 6% |
| After 2 |
126% |
Population of chickens at first = 100%
New population of chickens after first increase
= 100% + 20%
= 120%
Percentage of second increase
= 5% x 120%
=
5100 x 120%
= 6%
New population of chickens after second increase
= 120% + 6%
= 126%
126% of chicken population = 630
1% of the chicken population
= 630 ÷ 126
= 5
100% of chicken population
= 100 x 5
= 500
Number of chickens at first = 500
Answer(s): 500
