Xavier and Albert had 90 sweets each. Xavier gave 40% of his sweets to Albert. After receiving the sweets from Xavier, Albert gave 50% of his total sweets to Penelope. How many sweets had Albert left?
| |
Xavier |
Albert |
Penelope |
| Before |
100% |
100% |
|
| Change 1 |
- 40% |
+ 40% |
|
| After 1 |
60% |
140% |
|
| Change 2 |
|
- 70% |
+ 70% |
| After 2 |
|
70% |
|
Percentage of sweets after Albert received from Xavier
= 100% + 40%
= 140%
Percentage of Albert's sweets that Penelope had after receiving from Albert
= 50% x 140%
=
50100 x 140%
= 70%
Percentage of sweets that Albert had left after giving to Penelope
= 140% - 70%
= 70%
100% = 90
Number of sweets that Albert had left
= 70% x 90
=
70100 x 90
= 63
Answer(s): 63
