Xavier and Simon had 30 sweets each. Xavier gave 20% of his sweets to Simon. After receiving the sweets from Xavier, Simon gave 50% of his total sweets to Shiyun. How many sweets had Simon left?
| |
Xavier |
Simon |
Shiyun |
| Before |
100% |
100% |
|
| Change 1 |
- 20% |
+ 20% |
|
| After 1 |
80% |
120% |
|
| Change 2 |
|
- 60% |
+ 60% |
| After 2 |
|
60% |
|
Percentage of sweets after Simon received from Xavier
= 100% + 20%
= 120%
Percentage of Simon's sweets that Shiyun had after receiving from Simon
= 50% x 120%
=
50100 x 120%
= 60%
Percentage of sweets that Simon had left after giving to Shiyun
= 120% - 60%
= 60%
100% = 30
Number of sweets that Simon had left
= 60% x 30
=
60100 x 30
= 18
Answer(s): 18
