Marion made a profit of 60% from the sale of a sweater and a profit of 70% from the sale of a jumpsuit. The total profit she made from the two items was $84. She later sold a similar sweater at a discount of 10% off the advertised price. Her total profit for the three items then increased to $99.40.
- Find the profit made on the jumpsuit.
- How much did she sell the jumpsuit for?
|
Sweater 1 |
Jumpsuit 1 |
Sweater 2 |
Cost Price |
5 u |
10 p |
5 u |
Profit |
+ 3 u |
+ 7 p |
+ 3 u |
Selling Price |
8 u |
17 p |
8 u |
Discount |
|
|
- 0.8 u |
Discounted Price |
|
|
7.2 u |
100% + 60% = 160%
160% =
160100 =
85100% + 70% = 170%
170% =
170100 =
1710(a)
Selling price of the sweater
= 100% of the price of the sweater + 60% of the price of the sweater
= 5 u + 3 u
= 8 u
Selling price of the jumpsuit
= 100% of the price of the jumpsuit + 70% of the price of the jumpsuit
= 10 p + 7 p
= 17 p
Price of the second sweater after 10% discount in percentage
= 100% - 10%
= 90%
Price of the second sweater after 10% discount in units
= 90% x 8 u
=
90100 x 8 u
= 7.2 u
Profit made for the second sweater in units
= 7.2 u - 5 u
= 2.2 u
2.2 u = 99.4 - 84 = 15.4
1 u = 15.4 ÷ 2.2 = 7
3 u + 7 p = 84
3 x 7 + 7 p = 84
21 + 7 p = 84
7 p
= 84 - 21
= $63
Profit made on the jumpsuit = $63
(b)
1 p = 63 ÷ 7 = 9
Selling price of the jumpsuit
= 17 p
= 17 x 9
= $153
Answer(s): (a) $63; (b) $153