Kimberly made a profit of 50% from the sale of a sweater and a profit of 80% from the sale of a windbreaker. The total profit she made from the two items was $57. She later sold a similar sweater at a discount of 10% off the advertised price. Her total profit for the three items then increased to $68.90.

1. Find the profit made on the windbreaker.
2. How much did she sell the windbreaker for?

	Sweater 1	Windbreaker 1	Sweater 2
Cost Price	2 u	5 p	2 u
Profit	+ 1 u	+ 4 p	+ 1 u
Selling Price	3 u	9 p	3 u
Discount			- 0.3 u
Discounted Price			2.7 u

100% + 50% = 150%
150% = ¹⁵⁰₁₀₀ = ³₂

100% + 80% = 180%
180% = ¹⁸⁰₁₀₀ = ⁹₅

(a)
Selling price of the sweater
= 100% of the price of the sweater + 50% of the price of the sweater
= 2 u + 1 u
= 3 u

Selling price of the windbreaker
= 100% of the price of the windbreaker + 80% of the price of the windbreaker
= 5 p + 4 p
= 9 p

Price of the second sweater after 10% discount in percentage
= 100% - 10%
= 90%

Price of the second sweater after 10% discount in units
= 90% x 3 u
= ⁹⁰₁₀₀ x 3 u
= 2.7 u

Profit made for the second sweater in units
= 2.7 u - 2 u
= 0.7 u

0.7 u = 68.9 - 57 = 11.9

1 u = 11.9 ÷ 0.7 = 17

1 u + 4 p = 57
1 x 17 + 4 p = 57
17 + 4 p = 57

4 p
= 57 - 17
= $40

Profit made on the windbreaker = $40

(b)
1 p = 40 ÷ 4 = 10

Selling price of the windbreaker
= 9 p
= 9 x 10
= $90

Answer(s): (a) $40; (b) $90