Kimberly made a profit of 50% from the sale of a blazer and a profit of 60% from the sale of a shirt. The total profit she made from the two items was $41. She later sold a similar blazer at a discount of 20% off the advertised price. Her total profit for the three items then increased to $46.60.

1. Find the profit made on the shirt.
2. How much did she sell the shirt for?

	Blazer 1	Shirt 1	Blazer 2
Cost Price	2 u	5 p	2 u
Profit	+ 1 u	+ 3 p	+ 1 u
Selling Price	3 u	8 p	3 u
Discount			- 0.6 u
Discounted Price			2.4 u

100% + 50% = 150%
150% = ¹⁵⁰₁₀₀ = ³₂

100% + 60% = 160%
160% = ¹⁶⁰₁₀₀ = ⁸₅

(a)
Selling price of the blazer
= 100% of the price of the blazer + 50% of the price of the blazer
= 2 u + 1 u
= 3 u

Selling price of the shirt
= 100% of the price of the shirt + 60% of the price of the shirt
= 5 p + 3 p
= 8 p

Price of the second blazer after 20% discount in percentage
= 100% - 20%
= 80%

Price of the second blazer after 20% discount in units
= 80% x 3 u
= ⁸⁰₁₀₀ x 3 u
= 2.4 u

Profit made for the second blazer in units
= 2.4 u - 2 u
= 0.4 u

0.4 u = 46.6 - 41 = 5.6

1 u = 5.6 ÷ 0.4 = 14

1 u + 3 p = 41
1 x 14 + 3 p = 41
14 + 3 p = 41

3 p
= 41 - 14
= $27

Profit made on the shirt = $27

(b)
1 p = 27 ÷ 3 = 9

Selling price of the shirt
= 8 p
= 8 x 9
= $72

Answer(s): (a) $27; (b) $72